/*****************************************************************************
*       Outputs the sum of the digits of a three digit number.               *
*       Written: December 7, 2001                                            *
*       By: Ronald Roberts                                                   *
*****************************************************************************/
//Ronald Roberts
//7DEC01
//Program 56
#include <iostream.h>			
#include <math.h>
int calresults(int num);
int main()
{
int num=100;
while((num>=100 && num<1000) || (num<=-100 && num>-1000))
{
cout<<"Enter any 3-digit number (<100 or >999 to exit): ";
cin>>num;
cout<<"Sum of the digits: "<<calresults(num)<<endl;
}
cout<<"Goodbye."<<endl;
return 0;
}
int calresults(int num)
{
int a=num/100;
int b=num%10;
int c=(num%100)/10;
return a+b+c;
}
/*
Enter any 3-digit number (<100 or >999 to exit): 127
Sum of the digits: 10
Enter any 3-digit number (<100 or >999 to exit): 310
Sum of the digits: 4
Enter any 3-digit number (<100 or >999 to exit): 311
Sum of the digits: 5
Enter any 3-digit number (<100 or >999 to exit): 999
Sum of the digits: 27
Enter any 3-digit number (<100 or >999 to exit): -125
Sum of the digits: -8
Enter any 3-digit number (<100 or >999 to exit): -999
Sum of the digits: -27
Enter any 3-digit number (<100 or >999 to exit): 99
Sum of the digits: 18
Goodbye.
*/